hyptestingchisquaretests.ppt

  1. 1、本文档共39页,可阅读全部内容。
  2. 2、原创力文档(book118)网站文档一经付费(服务费),不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
  3. 3、本站所有内容均由合作方或网友上传,本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺!文档内容仅供研究参考,付费前请自行鉴别。如您付费,意味着您自己接受本站规则且自行承担风险,本站不退款、不进行额外附加服务;查看《如何避免下载的几个坑》。如果您已付费下载过本站文档,您可以点击 这里二次下载
  4. 4、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“版权申诉”(推荐),也可以打举报电话:400-050-0827(电话支持时间:9:00-18:30)。
查看更多
hyptestingchisquaretests

Presentation Hypothesis Testing Chi-Square Tests Module Objectives By the end of this module the participant will be able to Formulate appropriate hypotheses for Chi-Square Tests for Association Apply Chi-Square Tests for Association to practical problems Why Learn Chi-Square Test for Association? Make data driven decisions with defined confidence Determine if two attribute variables are related. What is the Chi-Square of Association? Chi-Square Test for Association To test if a relationship between two attribute variables exists The Chi-Square Distribution Measure of difference between observed counts and expected counts Observations must be independent Works best with 5 or more observations in each cell Cells may be combined to pool observations Test For Association What Is Chi-Square Test For Association? Tests the hypothesis of independence between two attribute variables Tests if the probabilities of items or subjects being classified for one variable depends upon the classification of the other variable Degrees of Freedom (df): Given we have a (r x c) contingency table, df = (r-1) * (c-1) Why Chi-square Test For Independence? Tests the hypothesis of independence between two variables Probabilities of items or subjects being classified for one variable are tested for dependence on the classifications of the other variable Random and Independent Sampling If expected frequencies are 5, sample size is sufficient Non-parametric test Does not require assumption of normality Used for attribute data Test For Independence Procedure State the practical problem: “Is the Y variable independent of the X variable?” Each combination has equal probability State the statistical problem: Ho : Y independent of X (no difference) Ha : Y dependent of X (at least one combination is different) Calculate the test statistic ?2 observed Determine the critical value of ?2 test statistic Reject the null hypothesis if ?2 observed ?2 critical or Reject the

文档评论(0)

taotao0c + 关注
实名认证
内容提供者

该用户很懒,什么也没介绍

1亿VIP精品文档

相关文档